Question

The pH of a solution obtaine by mixing `50 mL` of `0.4 N HCl` and `50 mL` of `0.2 N NaOH` is
A. log 2
B. `1.0`
C. `-log (0.05)`
D. `2.0`

Answer 1

Correct Answer - B
Acid left unconsumed `=(50 xx 0.2)/( 0.4)`
`=25 mL ` fo `0.4 N`
New normality of resulting solution
`=25 xx 0.4 -= 100xx N =0.1 N`
`pH =-log [10^(-1)]=1`