Question

The number of neutrons in `1*8` g of water will approximately be
A. `4*216xx10^(23)`
B. `8*432x10^(23)`
C. `4*816xx10^(23)`
D. `4*216xx10^(24)`

Answer 1

Correct Answer - C
`H_(2)O = 2_(1)^(1)H+._(8)^(16)O`
`:.` neutrons, `._(0)^(1)n = 0+8`
`.^(2)H_(2)O = (1*8)/(18) = 0*1`
Hence `._(0)^(1)n = 8xx0*1xx6*02xx10^(23)`
`=4*816xx10^(23)`