Question

If LPG cylinder contains mixture of butane and isobutane, then the amout of oxygen that would be required for combustion of 1 kg of it will be
A. `1*8 kg`
B. `2*7 kg`
C. `4*5 kg`
D. `3*58 kg`

Answer 1

Correct Answer - D
Equation of combustion is
`C_(4)H_(10) + 13//20_(2)to4CO_(2)+5H_(2)O`
Now 58 kg `C_(4)H_(10)` require `O_(2)`
`=13//2xx32 kg= 208 kg`
1 kg `C_(4)H_(10)` require `O_(2) = (13xx32)/(2xx58)kg=3*58kg`