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If `M` is the molecular weight of `KMnO_(4)`, its equivalent weight will be when it is converted into `K_(2)MnO_(4)`
A. `M`
B. `M//3`
C. `M//5`
D. `M//7`

1 Answer

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Best answer
Correct Answer - A
`2KMnO_(4)+2KOHto2K_(2)MnO_(4)+H_(2)O+[O]`
or `Moverset(+7)(n)O_(4)^(-)+e^(-)to overset(+6)(Mn)O_(4)^(2-)`
`:.` Eq. mass `=("Mol. Mass")/("Change in O.N.")=(M)/(1)=M`

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