Question

The electronegativity difference between two atoms A and B is `2`, then percentage of covalent character in the molecule is
A. `54%`
B. `46%`
C. `23%`
D. `72%`

Answer 1

Correct Answer - A
The percentage ionic character ionic character is related to electronegativity difference between the two atoms. It is given by Hanny and Smith relationship.
% age ionic character. =16`(X_A-X_B)+3.5(X_A-X_B)^2`
Here, `X_A and X_B` are electronegativities of two atoms A and B
`therefore` % ionic character =16(2)+`3.5(2)^2`=46%
or covalent character = 100-46 =54%