Correct option is: C) 4 : 1
Let the radius & height of the original cylinder be r & h respectively.
\(\therefore\) Volume of original cylinder is \(V_1 = \pi r^2 h\)
When the radius of base of cylinder is halved and height remaining same, then, the volume of formed cylinder is
\(V_2 = \pi (\frac r2)^2h = \frac {\pi r^2h}{4}\)
Now, \(\frac {V_1}{V_2}\) = \(\frac {\pi r^2h}{\frac {\pi r^2h}4}\) = \(\frac 41 = 4:1\)
Hence, the ratio of the volume of cylinder thus obtained to the volume of the original cylinder is 4 :1.