Correct option is (B) -1
Given that \(\alpha\;and\;\beta\) are zeros of \(x^2+x+1.\)
\(\therefore\) Sum of roots \(=\frac{\text{-coefficient of x}}{\text{coefficient of }x^2}=\frac{-1}1\) = -1
\(\Rightarrow\) \(\alpha+\beta\) = -1
And product of zeros \(=\frac{\text{constant term}}{\text{coefficient of }x^2}=\frac11\) = 1
\(\Rightarrow\) \(\alpha\beta=1\)
Now, \(\frac{\alpha+\beta}{\alpha\beta}=\frac{-1}1\) = -1
\(\Rightarrow\) \(\frac1\alpha+\frac1\beta\) = -1