Given, function is
Firstly we verify continuity at x = - 3 and then at x = 3. Continuity at x = -3
.'. f(x) is continuous at x = -3. So, x = - 3 is the point of continuity.
f is discontinuous at x = 3.
Now, as f(x) is a polynomial function for x < - 3, - 3 < x < 3 and x > 3, so it is continuous in these intervals.
Hence, only x = 3 is the point of discontinuity of f(x).