Correct option is: D) 9.5 m
In right \(\triangle\)ABC,
\(\frac {AB}{AC}\) = cos A = cos \(60^\circ\) (\(\because\) \(\angle\)CAB = \(60^\circ\))
\(\therefore\) AB = AC cos \(60^\circ\)
= \(\frac {19}2\) (\(\because\) cos \(60^\circ\) = \(\frac {1}2\) & AC = 19 m)
= 9.5 m
Hence, the distance of foot of ladder from the foot of the wall is 9.5 m.