Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
49 views
in Chemistry by (70.2k points)
closed by
Componds `(A)` and `B` are treated with dilute `HCl` separately. The gases liberated are `Y` and `Z` respectively. `Y` turns acidified `K_2 Cr_2 O_7` paper green while `Z` turns lead acetate paper black. The compounds `A` and `B` are respectively :
A. `Na_(2)S " and " Na_(2)SO_(3)`
B. `Na_(2)SO_(3) " and " Na_(2)S`
C. `NaCl " and" Na_(2)CO_(3)`
D. `Na_(2)SO_(3) " and " na_(2)SO_(4)`

1 Answer

0 votes
by (72.1k points)
selected by
 
Best answer
Correct Answer - B
`underset((A))Na_(2)SO_(3)+2HCl (aq) to 2NaCl+H_(2)O+underset((X))SO_(2)`
`K_(2)Cr_(2)O_(7)+H_(2)SO_(4) + underset((X))3SO_(2) to underset(("Green"))(Cr_(2)(SO_(4))_(3))+K_(2)SO_(4)+H_(2)O`
`underset((B))(Na_(2)S)+HCl(aq) to 2NaCl+underset((Y))(H_(2)S)`
`underset((Y))(H_(2)S)+Pb(CH_(3)COO)_(2) to underset(("Black"))(PbS+2CH_(3))COOH`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...