Correct option is: D) \(\frac {n+1}2\)
First n natural numbers are 1, 2, 3,.....,.n
Mean = \(\frac {sum\, of \,first \,n \,natural \,numbers}n\) = \(\frac {1+2+3+.....+n}n\)
= \(\frac {\frac {n(n+1)}2}{n} = \frac {n (n+1)}{2n} = \frac {n+1}2\)
Hence, mean of first n natural numbers is \(\frac {n+1}2\).