Question

Find the equation of tangent to the curve y = (x - 7)/(x² - 5x + 6) at the point, where it cuts the X -axis.

Answer 1

Given, equation of curve is 

y = (x - 7)/(x² - 5x + 6)    .....(i)

On differentiahng both sides w.r.t. x, we get

[dividing numerator and denominator by x² - 5x + 6]

Also, given that curve cuts X-axis, so its y-coordinate is zero.

Put y = 0 in Eq. (i) we get

Hence, the required equation of tangent passing through the point (7, 0) having slope 1/20 is