Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
208 views
in Chemistry by (91.1k points)
closed by
0.16 g of methane was subjected to combustion at `27^(@)C` in a bomb calorimeter. The temperature of Calorimeter system (including water) was found to rise by `0.5^(@)C`. Calculate the heat of combustion of methane at
(i) constant volume (ii) constant pressure.
The thermal capacity of Calorimater system is `17.7" kJ K"^(-1)`. `(R=8.313" J mol"^(-1) K^(-1))`

1 Answer

0 votes
by (91.4k points)
selected by
 
Best answer
Correct Answer - (i) -885 kJ/mol (ii) -889.95 kJ/mol
`CH_(4)+2O_(2) rarr CO_(2) +2H_(2)O`
Total energy relesed `=17.7xx0.5=8.85`
Energy released by one mole `CH_(4)=8.85/0.16 xx16=-885" kJ/mol"`
`DeltaH=DeltaU+Deltan_(g) RT rArr Deltan_(g) =-1 rArr DeltaH=-889.95" kJ/mol"`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...