Question

To find molelular mass of diabasic acid by silver salt method following graph is plotted then approximate molecular weight of acid is -
where y = weight of silver residue ( in gm)
x = weight of silver salt (in gm)

A. 160 gm
B. 158 gm
C. 320 gm
D. 240 gm

Answer 1

Correct Answer - A
`tan 30^(@) = (W_(Ag))/(W_(Ag - "Salt")) = (1)/(sqrt3)`
`(W_("salt"))/(W_(Ag)) = sqrt3`
`M_(wt) "of" H_(2)X = 2 (108 (W_("Salt"))/(W_(Ag )) - 107)`
`= 2 (108 xx sqrt3 - 107)`
`= 2 (187.056 - 107)`
`= 2 xx 80.056`
`= 160.112 gm`