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Consider a square ABCD of side 12 and let M, N be the midpoints of AB, CD respectively. Take a point P on MN and let AP=r, PC=s. Then the area of the

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Consider a square ABCD of side 12 and let M, N be the midpoints of AB, CD respectively. Take a point P on MN and let AP=r, PC=s. Then the area of the triangle whose sides are r, s, 12 is-
A. 72
B. 36
C. `(rs)/(2)`
D. `(rs)/(7)`
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Correct Answer - B
image
PA=r, PC = s
So PB = r
Triangle with sides r, s & 12 is `DeltaPCB`
image
`"area"=(1)/(2)"base"xx"height"=(1)/(2)xx6xx12=36`
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