Calculatetion of molality of solution

Weight of water in the solution= 20 g

Weight of water in the solution=100-20=80g=0.08 kg

Molar mass of KL=39+127=166g `mol^(-1)`.

`"Molality of solution (m)"=("No of gram moles of KL")/("Mass of water in kg")=((20g)//(166g mol^(-1)))/((0.08 kg))`

Calucalation of molarity of solution

` "Weight of solution"=100g , "Density of solution" = 1.202g mL^(-1)`.

`"Volume of solution"=("Weight of solution")/("Density")=((100g))/((1.202g mL^(-1)))=83.19 mL=0.083L`

`"Molarity of solution (m)"=("No. of gram moles of KL")/("Voluume of solution in litres")=((20g)//(166g mol^(-1)))/((0.083L))`

Calculation of mole fraction of KL

`n_(KL)=("Mass of KL")/("Molar mass of KL")=((20g))/((166g mol^(-1)))=0.12 mol`

`n_(H_(2)O)=("Mass of water")/("Molar mass of water")=((80g))/((18g mol^(-1)))=4.44 mol`

`x_(KL)=n_(KL)/(N_(KL)+n_(H_2O))=((0.12 mol))/((0.12+4.44)mol)=(0.12)/(4.56)=0.0263.`