Correct Answer - 8.12 M
Mass of ethylene glycol = 222 g
Mass of water = 250 g
Mass of solution = (222+250)=472 g
Density of solution = 1.07 g `mL^(-1)`
`"Volume of solution (M) "=("Mass os ethylene glycol/molar mass")/("Volume os solution in litres")`
`=((222g))/((62" g mol"^(-1))xx(0.4412L))`
=8.12 mol `L^(-1)`=8.12 M