Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
56 views
in Chemistry by (91.0k points)
closed by
6.3 g of exalic acid (eq.wt=63) is dissoved in 500 mL. solution. What will be the normality of the solution ?

1 Answer

0 votes
by (91.3k points)
selected by
 
Best answer
Correct Answer - 0.2 M
`"Normalioty of solution (N)"=("Mass of oxalic acid/Equivalent mass")/("Volume of solution in litres")`
`"Mass os oxalic acid = 6.3 g, Equivalent mass of oxalic acid "= 63" g equiv"^(-1)`,
`"Volume of solution=500 mL="500/1000=0.5 L`
`"Normality (N)"=((6.3g)/(63" g equiv"^(-1)))/((0.5L))=0.2"equiv L"^(-1)=0.2N.`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...