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Ethylene glycol is used as antifreeze in a cold climete. Mass of ethylene glycol which should be added to 4 kg of water = 1.86 K kg `mol^(-1)`, molar mass of ethylene glycol = 62 g `mol,^(-1)` )
A. 804.32 g
B. 204.30 g
C. 400.-- g
D. 304.60 g

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Correct Answer - a
`=((62h mol^(-1))xx(6K)xx(4kg))/((1.86"K kg" mol^(-1)))=800 g`

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