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in Chemistry by (91.1k points)
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Weight of urea requied to prepare 200 mL of 2M solution as :
A. 12 g
B. 24 g
C. 20 g
D. 60 g

1 Answer

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Best answer
Correct Answer - b
`((0.2 molL^(-1))xxW)/((60g mol^(-1))xx(0.2L))`
`W=(0.2 mol L^(-1))xx(60g mol^(-1))xx(0.2L)`
=24g.

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