Question

The ionization enegry of the electron in the hydrogen atom in its ground state is `13.6 ev`. The atoms are excited to higher energy levels to emit radiations of `6` wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between
A. n=3 to n=1 states
B. n=4 to n=3 states
C. n=3 to n=2 states
D. n=2 to n=1 states

Answer 1

Correct Answer - B
Number of wavelelngth =`(n(n-b))/(2)`
where, n=number of orbit from which transition place
`:. " " 6=(n(n-1))/(2)rArrn=4`
`:.` The wavelength of emitted radiations will be maximum for transition n=4 to n=3