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asked in Chemistry by (368 points)
edited by

Solve the reaction.

1 Answer

+2 votes
answered by (9.5k points)
edited by


I made a mistake. Your answer option B is correct


Protonation of oxygen atom opens the epoxide ring forming a secondary carbo cation as well as a -OH group.

A 5 membered ring formation then occurs due delocalization of electron from =CHforming a tertiary carbocation. This carbocation is then attacked by water molecule and finally a -OH group is formed there releasing a proton.

commented by (368 points)
Please can u write the chemical reaction.
commented by (9.5k points)
Using phone now. I can try it later from desktop.
commented by (368 points)
Okk.Thank You
commented by (368 points)
Thank you for the answer.

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