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Find:  ∫x3/(x4 + 3x2 + 2) dx

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Best answer

\(\int \frac{x^3}{x^4 + 3x^2 + 2}dx\)

\(x^2 =u\)

\(2xdx = du\)

\(\int \frac{x^2 . x\,dx}{(x^2)^2 + 3x^2 + 2}\)

\(=\frac 12 \int \frac {u\, du}{u^2 + 3u + 2} \)

\(= \frac 12 \int \frac u{(u + 1)(u + 2)} du\)

\(=\frac12 \int \left( \frac 2{u + 2} - \frac 1{u + 1}\right)du\)

\(= \ln |u + 2| - \frac12 \ln |u + 1| + C\)

\(= \ln |x^2 + 2| - \frac 12 \ln|x^2 + 1|+C\)

+2 votes
by (34.7k points)

Given integral

Let  x2 = t

2x dx = dt

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