Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Physics by (91.4k points)
closed by
Two coherent sources separated by distance d are radiating in phase having wavelength `lambda`. A detector moves in a big circle around the two sources in the plane of the two sources. The angular position of `n=4` interference maxima is given as
image
A. `"sin"^(-1) (nlambda)/d`
B. `"cos"^(-1) (4lambda)/d`
C. `"tan"^(-1)d/(4lambda)`
D. `"cos"^(-1)lambda/(4d)`

1 Answer

+1 vote
by (91.3k points)
selected by
 
Best answer
Correct Answer - B
Path difference at a point Q on the circle is
image
`Deltay=dcos theta`
For maxima at Q path difference should be integer multiple of wavelength
`Deltay=nlambda`
From Eqs. (i) and (ii)
`nlambda=dcos theta`
`:. theta=cos^(-1)((nlambda)/d)`
For `n=4`
Angular position `theta=cos^(-1) ((4lambda)/d)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...