Let x and y units of packet of mixes are purchased from S and T respectively. if Z is the total cost, then

Z = 10x+4y ....(i)

is objective function which we have to minimize Here constraints are

4x+y ≥ 80 ...(ii)

2x+y ≥ 60 ...(iii)

x ≥ 0 ..(iv)

y ≥ 0 ....(v)

On plotting the graph o{ above constraints or inequalities (ii), (iii), (iv) and (v), we get shaded region having corner point A, P, B as feasible region.

For co-ordinate of P

Since the graph of inequality (viii) does not have any point common.

So the minimum value of Z is 260 at (10,40). i.e., minimum cost of each bottle is ₹260 if the company purchases 10 packets of mixes from S and 40 packets of mixes from supplier T.