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`Fe(OH)_(3)` and `Cr(OH)_(3)` precipitates can be completely separated by `:`
A. Aqueous `NH_3`(cold )
B. HCl
C. `NaOH//H_2O_2`
D. `H_2SO_4`

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Correct Answer - C
`Cr(OH)_3+OH^(-)hArr [Cr(OH)_4]^(-)`
`2[Cr(OH)_4]^(-)+2OH^(-)+3H_2O_2 to 2CrO_4^(2-)` (yellow colour solution)+`8H_2O`
`Fe(OH)_3` remains as brown precipitate.

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