Question

Two blocks of masses 2 kg and 1 kg are in contact with each other on a frictionless table. When a horizontal force of `3.0` N is applied to the block of mass 2 kg the value of the force of contact between the two blocks is:
A. 4N
B. 3N
C. 5N
D. 1N

Answer 1

`a=(3)/(3)=1m//s^(2)`
N=ma(for 1 kg body)=1N