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A block slides down a rough inclined plane of slope angle `theta` with a constnat velocity. It is then projected up the same plane with an intial velocity v the distance travelled by the block up the plane coming to rest is .
A. `(v_(0)^(2))/(2g sin theta)`
B. `(v_(0)^(2))/(4g sin theta)`
C. `(v_(0)^(2)sin^(2)theta)/(2g)`
D. `(v_(0)^(2)sin^(2)theta)/(4g)`

1 Answer

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Best answer
Correct Answer - B
`mg sin theta=mu mg cos theta`
when pushed up
deacc `=g sin theta+mug cos theta`
`therefore v^(2)-v_(0)^(2)=2(a)xxs`
`therefore s=(v_(0)^(2))/(2(2g sin theta))`

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