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A Zener diode is specified having a breakdown voltage of 9.1 V with a maximum power dissipation of 364 mW. What is the maximum current that the diode

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A Zener diode is specified having a breakdown voltage of 9.1 V with a maximum power dissipation of 364 mW. What is the maximum current that the diode can handle.
A. 40 mA
B. 60 mA
C. 50 mA
D. 45 mA
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Correct Answer - A
The maximum permissible current is
`I_(Z_("max"))=P/V_z=(364xx10^(-3))/9.1=40 mA`
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