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A p-n photodiode is made of a material with a band gap of 2 e V. The minimum frequency of the radiation that can be absorbed by the material is nearly
(hc= 1240 eV nm)
A. `1xx10^14` Hz
B. `20xx10^14` Hz
C. `10xx10^14` Hz
D. `5xx10^14` Hz

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Correct Answer - D
Here, `E_g` =2eV
Wavelength of radiation corresponding to this energy is
`lambda=(hc)/(E_g)=(1240 eV nm)/(2 eV)=620 nm`
Frequency `upsilon =c/lambda=(3xx10^8 m s^(-1))/(620xx10^(-9)m)=5xx10^14` Hz.

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