Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
68 views
in Physics by (91.3k points)
closed by
For a common emitter transistor amplifier, the audio signal voltage across the collector resistance of `2 kOmega` is 2 V. Suppose the current amplification factor of the transistor is 100, the base current if base resistance is `1 k Omega` is
A. `10 muA`
B. `20 muA`
C. `5 muA`
D. `2 muA`

1 Answer

0 votes
by (91.0k points)
selected by
 
Best answer
Correct Answer - A
Here, `R_C=2 kOmega =2000 Omega, R_B=1 kOmega=1000 Omega, beta=100, V_o=2V`
`therefore beta=I_C/I_B=(V_o//R_C)/I_B`
`therefore` Base current , `I_B=V_o/(betaR_C)=2/(100xx2000)=10^(-5) A=10 muA`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...