Correct Answer - C
The output from the upper AND gate =`(barA.B)`
The output from the lower AND gate =`(A.barB)`
The output y of the NOR gate is
`y=bar((barA.B)+(A.barB))`
`=bar((barA.B))+bar((A.barB))=(A+barB)(barA+B)`
`=AbarA+AB+barBbarA+barB B=AB+barAbarB`