Given curves are

x - y + 2 = 0, ...........(i)

the curve x = √y ..........(ii)

Consider x = √y or x^{2} = y, which represents the parabola whose vertex is (0, 0) and axis is Y-axis.

Now, the point of intersection of Eqs. (i) and (ii) is given by

But x = - 1 does not satisfy the Eq. (ii)

x = 2

Now, putting x = 2 in Eq. (ii), we get

2 = √y or y = 4

Hence, the point of intersection is (2,4).

But we have actual equation of parabola x = √y, it means a semi-parabola which is one right side of Y-axis.

The graph of given curve area shown below :

Clearly, area of bounded region = Area of region OABO