Given curves are
x - y + 2 = 0, ...........(i)
the curve x = √y ..........(ii)
Consider x = √y or x2 = y, which represents the parabola whose vertex is (0, 0) and axis is Y-axis.
Now, the point of intersection of Eqs. (i) and (ii) is given by
But x = - 1 does not satisfy the Eq. (ii)
x = 2
Now, putting x = 2 in Eq. (ii), we get
2 = √y or y = 4
Hence, the point of intersection is (2,4).
But we have actual equation of parabola x = √y, it means a semi-parabola which is one right side of Y-axis.
The graph of given curve area shown below :
Clearly, area of bounded region = Area of region OABO