Question

1, 4, 9, 16, ………………. sum to ‘n’ terms =

A) \(\cfrac{n^2(n+1)^2}4\)

B) \(\cfrac{n(n+1)(2n+1)}6\)

C) \(\cfrac{(n+1)(2n+1)}3\)

D) \(\cfrac{n(n+1)}2\)

Answer 1

Correct option is B) \(\cfrac{n(n+1)(2n+1)}6\)