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Find the particular solution of the differential equation :  dy/dx + y cot x = 2x + x2 cot x, x ≠ 0. Given that x = 0, when x = pi/2

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The given equation is a linear differential equation of the type

Hence, the solution of the differential equation is given by :

Substituting y = 0 and x = pi/2, in the above equation (i), we get

Now substituting this value in eq. (i), we get

This is the required particular solution of the given differential equation.

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