# Find the particular solution of the differential equation : dy/dx + y cot x = 2x + x^2 cot x, x ≠ 0.

77.1k views

Find the particular solution of the differential equation :  dy/dx + y cot x = 2x + x2 cot x, x ≠ 0. Given that x = 0, when x = pi/2

by (30.5k points)
selected

The given equation is a linear differential equation of the type

Hence, the solution of the differential equation is given by :

Substituting y = 0 and x = pi/2, in the above equation (i), we get

Now substituting this value in eq. (i), we get

This is the required particular solution of the given differential equation.