Question

Two reactiosn of same order have equal pre-exponential factors but their activation energies differ by 41.9 J/mol. Calculte the ratios between rate constant of these reactions at 600 K

Answer 1

Correct Answer - `0.002`
Use the relation
`log_(10)k=log_(10)A-(E)/(2.303RT)" ".....(i)`
`log_(10)k_(1)=log_(A)-(E_(1))/(2.303xx8.314xx600) " ".....(ii)`
`log_(10)k_(2)=log_(A)-(E_(2))/(2.303xx8.314xx600) " ".....(iii)`
`E_(1)-E_(2)=41.95//"mol"" ".....(iv)`
Substract eq. (ii) from eq. (ii) to determine the ratio