Correct Answer - B
`X-Y` axis
`mu_(1) sintheta_(1)=mu_(2)sintheta_(2)`
`costheta_(1)=(10)/(sqrt((6sqrt3)+(8sqrt(3))^(2)+100))=(10)/(sqrt(400))=(10)/(20)`
`costheta_(1)=(1)/(2)`
`theta_(1)=60^(@)`
`sqrt2 sin60^(@)=sqrt3 sintheta_(2)`
`sqrt2xx(sqrt3)/(2)=sqrt3sintheta_(2)`
`sintheta_(2)=(1)/(sqrt2)`
`theta=45^(@)`