# Find the particular solution of the differential equation : ye^y dx = (y^3 + 2xe^y)dy, y(0) = 1

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Find the particular solution of the differential equation : yey dx = (y3 + 2xey)dy, y(0) = 1

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yey dx = (y3 + 2xey)dy, y(0) = 1

which is linear in x.

Multiplying both sides by the I.F. and integrating, we get,

Hence, the required particular solution is