# A compound microscope has an objective of focal length 2.0 cm and an eye-piece of focal length 6.25cm and distance between the objective and eye-p

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A compound microscope has an objective of focal length 2.0 cm and an eye-piece of focal length 6.25cm and distance between the objective and eye-piece is 15cm. If the final image is formed at the least distance vision (25 cm), the distance of the object form the objective is

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Correct Answer - (a) v_(0) = -2.5cm and f_(e) = 6.25cm give mu_(e) = -5cm; v_(0) = (15-5)cm = 10cm
f_(0) = u_(0) = -2.5cm;
Magniflying power = (10)/(2.5) xx (25)/(5) = 20
(b) mu_(e) = -6.25cm, v_(0) = (15-6.25)cm = 8.75, f = 2.0cm. Therefore
u_(0) = -(70//27) = -2.59cm
Magnifying power
= (v_(0))/(|u_(0)|) xx (25//6.25) = (27)/(8) xx 4 = 13.5
(a) v_(e) = -2.5cm and f_(e) = 6.25cm give u_(e) = -5cm, v_(0) = (15-5)cm = 10cm.
f_(0) = u_(00 = -2.5cm, Magnifying power = (10)/(2.5) xx (25)/(5) = 20
(b) u_(theta) = -6.25cm, v_(o) = (15-6.25)cm = 8.75, f_(0) = 2.0cm. Therefore
mu_(0) = -(70//27) = -2.59cm
Magnifiying power = (v_(0))/(|mu_(0)|) xx (25//6.25) = (27)/(8) xx 4 = 13.5