Correct Answer - (a) `v_(0) = -2.5cm` and `f_(e) = 6.25cm` give `mu_(e) = -5cm; v_(0) = (15-5)cm = 10cm`

`f_(0) = u_(0) = -2.5cm;`

Magniflying power `= (10)/(2.5) xx (25)/(5) = 20`

(b) `mu_(e) = -6.25cm, v_(0) = (15-6.25)cm = 8.75, f = 2.0cm`. Therefore

`u_(0) = -(70//27) = -2.59cm`

Magnifying power

`= (v_(0))/(|u_(0)|) xx (25//6.25) = (27)/(8) xx 4 = 13.5`

(a) `v_(e) = -2.5cm` and `f_(e) = 6.25cm` give `u_(e) = -5cm, v_(0) = (15-5)cm = 10cm`.

`f_(0) = u_(00 = -2.5cm,` Magnifying power `= (10)/(2.5) xx (25)/(5) = 20`

(b) `u_(theta) = -6.25cm, v_(o) = (15-6.25)cm = 8.75, f_(0) = 2.0cm`. Therefore

`mu_(0) = -(70//27) = -2.59cm`

Magnifiying power `= (v_(0))/(|mu_(0)|) xx (25//6.25) = (27)/(8) xx 4 = 13.5`