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in Mathematics by (31.6k points)

Find the equation of a plane which passes through the point (3,2, 0) and contains the line x-3/1 = y-6/5 = z-4/4.

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The equation of a plane passing through a point (3, 2,0) is a (x-3) + b(y -2) + c(z-0) = 0   ......(i)

Since, the above plane contains the line

x-3/1 = y-6/5 = z-4/4

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