Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
31.6k views
in Physics by (6.2k points)

A particle crossing the origin of co-ordinates at time t = 0, moves in the xy-plane with a constant acceleration a in the y-direction. If its equation of motion is y = bx2 (b us a constant), its velocity component in the x-derection is

(a) √2b/a

(b) √a/2b

(c) √a/b

(d) √b/a

(e) √ba

1 Answer

+1 vote
by (12.0k points)
selected by
 
Best answer

Correct Option  (b) √a/2b

Explanation:

y = bx2

Differentiating w.r.t. t, on both sides, we get

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...