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The standard deviation of first 10 natural numbers is 8.25 (b) 6.5 (c) 3.87 (d) 2.87

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The standard deviation of first 10 natural numbers is 8.25 (b) 6.5 (c) 3.87 (d) 2.87
A. 5.5
B. 3.87
C. 2.97
D. 2.87
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Correct Answer - D
We know that, SD of first n natural numbers`=sqrt((n^(2)-1)/(12))`
`therefore` SD of first 10 numbers `=sqrt((10^(2)-1)/(12))`
`=sqrt((100-1)/(12))=sqrt((99)/(12))=sqrt(8.25)=2.87`
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