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Find the equation of plane containing the lines x -8/3 = y+19/-16 = z-10/7 and x-38/3 = y+29/8 = z-5/-5.

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Find the equation of plane containing the lines

x -8/3 = y+19/-16 = z-10/7 and x-38/3 = y+29/8 = z-5/-5.

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Clearly required plane passes through point (8, -19, 10) and normal to plane is perpendicular to given lines so equation of plane is given by

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