Question

In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow
`P = (a^(3)b^(2))/(cd) %` error in `P` is
A. 0.04
B. 0.14
C. 0.1
D. 0.07

Answer 1

`P=(a^(3)b^(2))/(cd)rArr(Deltap)/(P)=+-(3(Delta)/(a)+2(Deltab)/(b)+(Deltac)/(c)+(Deltad)/(d))`
`=+-(3xx1+2xx2+3+4)`
`=+-14%`