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The medians AD and BE of the triangle with vertices A(0, b), B(0, 0) and C (a, 0) are mutually perpendicular if

(1) b = 2a

(2) a = 2b

(3) b = – 2a

(4) a = – 2 2b

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(2) a = 2b


The coordinates of D and E are (a/2, 0) and (a/2, b/2) respectively

Since AD and BE are perpendicular, therefore

m1m2 = -1

-(2b/a).b/a = -1

a = ±2b

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