Question

Spin magnetic moment of `X^(n+) (Z=26)` is `sqrt(24) B.M.` Hence number of unpaired electrons and value of `n` respectively are:
A. `4, 2`
B. `2, 4`
C. `3, 1`
D. `0, 2`

Answer 1

Correct Answer - A
Magnetic moment `=sqrt(n(n+2))=sqrt(24) B.M.`
`:.` No. of unpaired electron `=4`
`X_(26): 1s^(2) 2s^(2)2p^(6)3s^(2)3p^(6)3d^(6)4s^(2)`.
To get `4` unpaired electrons, outermost configuration cinfiguration will be `3d^(6)`
`:.` No. of electrons lost `=2 ("from" 4s^(2))`
`:. n=2`