Prove that In a right triangle, if the square of one side is equal to the sum of the squares of the other two sides,

Question

Converse of Pythagoras Theorem:

Prove that In a right triangle, if the square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle.

Answer 1

Proof: Here we are given a triangle ABC in which AC² = AB² + BC²

We need to prove that ∠B = 90°

To start with, we construct a ΔPQR right angled at Q such that PQ = AB and QR = BC