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The spin-only magnetic moment [in units of Bohr magneton, `(mu_(B)` of `Ni^(2+))` in aqueous solution would be (atomic number of `Ni=28)`
A. `2.84`
B. `4.90`
C. `0`
D. `1.73`

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Best answer
Correct Answer - 1
`_(28)Ni rarr[Ar]3d^(8) 4s^(2)`
image
Number of unpaired electrons `(n)=2`
`mu=sqrt(n(n+2))=sqrt(2(2+2))=sqrt(8) ~~ 2.84`

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