Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
93 views
in Chemistry by (80.6k points)
closed by
A thermally isolated vessel contains `100g` of water at `0^(@)C`. When air above the water is pumped out, some of the water freezes and some evaporates at `0^(@)C` itself. Calculate the mass of the ice formed such that no water is left in the vessel. Latent heat of vaporization of water at `0^(@)C=2.10xx10^(6)J//kg` and latent heat of fusion of ice `=3.36xx10^(5)J//kg`.

1 Answer

0 votes
by (80.9k points)
selected by
 
Best answer
Total mass of the water `=M=100g`
Latent heat of vaporization of water at `0^(@)C`
`=L_(1)=21.0xx10^(5)J//Kg`
& Latent heat of fusion of ice `=L_(2)=3.36xx10^(5)J//kg`
Suppose, the mass of the ice formed `=m`
Then, the mass of water evaporated `=M-m`
Heat lost by the water in freezing`=` Heat taken by water in evaporation.
Thus, `mL_(2)=(M-m)L_(1) or m-86 g`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...